Re: [PHP] glob(path_pattern, GLOB_ONLYDIR)

Al wrote:
I thought the "." had meaning since the manual user notes used it

it means a literal dot, many people assume that glob expressions
use the same syntax as regular expressions but this is not the case.


Definitely, my php is version 4.4.4; it's on a virtual host.

I found the glob file for the GNU C Library and GLOB_ONLYDIR doesn't
seem to be defined correctly, the file appears to rather old.

I used the numerical value "8196" and it works fine. I'm a little
reluctant to use the numerical value as I want my code to be generally
universal. Maybe the numerical value is safer anyhow. What do you think?

you might consider something like this:

if (!defined('GLOB_ONLYDIR'))
define('GLOB_ONLYDIR', 8196);

I doubt that the numeric value will ever change btw.


I can alternatively just filter out the files in a second step.

that seems like a lesser solution.


Al.............



Jim Lucas wrote:
Al wrote:
I can't use flag "GLOB_ONLYDIR" to work on a Linux, php4.4.4. I only
want the dirs.

This works; sort of:
print_r(glob('../*',)); //It lists all the files AND directories.
Yet it seems to ignore the lack of ".*" and finds xxx.yyy. That's OK,
I can delete the files
remember this is linux you are talking about, not windows.

A '*' means anything, including a '.'



This fails:
print_r(glob('../*', GLOB_ONLYDIR));
well, double check your php version, because this should be built in
whit the version that you are running.


And I get: "Warning: glob() expects parameter 2 to be long, string
given in foo"

I can't find anything in the manual or when Googling.

Anyone can explain this for me?


.

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