Re: [PHP] simple page not found 404 script - PHP

2007. 03. 30, péntek keltezéssel 15.56-kor Dwayne Heronimo ezt írta:
When I echo the $pagename it returns the correct string. I also tried to
rename the $pagename to something I am sure that wouldn't come up in other
scripts.
One thing that is coming up in other scripts is the $_GET['catcode'] because
I am using queries with this to show the categories.

where did you put that echo? you should put it right before the
if (file_exists("$pagename"))
row
btw, if you pass only the variable, you don't need those quotes around
it - they only consume resources in this case. so:
if (file_exists($pagename))

but I must admit I have no more ideas. if $pagename is correct right
before the if, and still both the if part and the else part gets
executed thats beyond my knowledge...

one more thought: do you have any kind of code after this if?
maybe you just forget that you include some displaying part after it and
that's making the confusion...

greets
Zoltán Németh


wierd i tried renaming the
""Zoltn Nmeth"" <znemeth@xxxxxxxxxxxxxx> wrote in message
news:1175262041.5023.62.camel@xxxxxxxxxxxxxxx
well, I don't know what may be wrong...
try echoing out $pagename
and is your script only this? or are there other parts? if so, those
other parts might be screwing things up...

greets
Zoltn Nmeth

2007. 03. 30, pntek keltezssel 15.36-kor Dwayne Heronimo ezt rta:
hey zoltan,

I used your code but this still is displaying both the 404 and the normal
page:

http://arubaguide.org/arubaguide/categories.php?catcode=activities


<?php
$pagename = $_GET['catcode'];
if(file_exists("$pagename")) {
include "$pagename";
} else {
include "404.php";
}
?>



""Zoltn Nmeth"" <znemeth@xxxxxxxxxxxxxx> wrote in message
news:1175260687.5023.56.camel@xxxxxxxxxxxxxxx
2007. 03. 30, pntek keltezssel 15.10-kor Dwayne Heronimo ezt rta:
indeed.. it should be catcode instead of page.:-(. but still its not
working
:S



<?php

/* function to get an external file into a vatiable */
function get_include_contents($filename) {
if (is_file($filename)) {
ob_start();
include $filename;
$contents = ob_get_contents();
ob_end_clean();
return $contents;
}
return false;
}

/* configuration file */

$errormsg = get_include_contents('404.php');
$pagename = $_GET['catcode'];

/* end configuration file */

if(file_exists("$pagename"))
{
include "$pagename";
}
else
{
echo "$errormsg";
}
?>


actually I don't know what the problem is, but I would do it in a much
shorter way:

$pagename = $_GET['catcode'];
if(file_exists("$pagename")) {
include "$pagename";
} else {
include "404.php";
}

about your original question, the script looks basically okay... what
is
the error you get?

greets
Zoltn Nmeth



""Zoltn Nmeth"" <znemeth@xxxxxxxxxxxxxx> wrote in message
news:1175259498.5023.49.camel@xxxxxxxxxxxxxxx
2007. 03. 30, pntek keltezssel 14.45-kor Dwayne Heronimo ezt rta:
Dear All,

I have made a simple php script that will show an 404.php error
page
when
an
item is removed.

You can see the page here:
http://arubaguide.org/arubaguide/categories.php?catcode=art

But some how this is not working. It is displaying the 404 page and
the
normal page.

in the above link you do not give a "page" parameter at all... so
from
where should the script get it?

greets
Zoltn Nmeth



<?php

/* function to get an external file into a vatiable */
function get_include_contents($filename) {
if (is_file($filename)) {
ob_start();
include $filename;
$contents = ob_get_contents();
ob_end_clean();
return $contents;
}
return false;
}

/* configuration file */

$errormsg = get_include_contents('404.php');
$pagename = $_GET['page'];

/* end configuration file */

if(file_exists("$pagename"))
{
include "$pagename";
}
else
{
echo "$errormsg";
}
?>

is the $pagename not enough for this script?

Let me know..

Dwayne




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