Re: [PHP] Selecting Rows Based on Row Values Being in Array
- From: lists@xxxxxxxxx (Jim Lucas)
- Date: Fri, 29 Jun 2007 23:46:20 -0700
kvigor wrote:
Hello All,I would suggest approaching the problem with a slightly different thought.
I'm attempting to return rows from a mysql DB based on this criteria:
I have a list, in the form of an array that I need to compare against each row
in the table. Where theres a match I need that entire row returned.
e.g. $varListof 3outOf_10Fields = array(6blue40lbs, 7orange50lbs, 8orange60lbs, 9purple70lbs);
The array contains 3 of the db row fields in 1 value. However there are 10 fields/columns in the table.
===============
what table looks like |
===============
size color weight
ROW 1 | value1 | value1 | value1 | value1 | value1 | value1 |
So how could I set up a query that would SELECT the entire row, if the row contained $varListof 3outOf_10Fields[1].
Open to any suggestions or work arounds. I'm playing with extract() but code is too crude to even post.
just have the sql concat() the columns together and then compare.
something like this should do the trick
$list = array(
'6blue40lbs',
'7orange50lbs',
'8orange60lbs',
'9purple70lbs',
);
$SQL = "
SELECT *
FROM my_Table
WHERE CONCAT(value1, value2, value3) IN ('".join("','", $list)."')
";
mysql_query($SQL);
this should take, for each row in the DB, value1 + value2 + value3 and create one string from them, then it will compare each string in the
IN (...) portion to each entry in the $list array().
Let me know if you need any further help
.
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