Re: [PHP] GD, changing an images pixel color, color matching, fuzzy picture
- From: heavyccasey@xxxxxxxxx (Casey)
- Date: Fri, 28 Mar 2008 19:03:11 -0700
On Mar 28, 2008, at 4:27 PM, Lamonte <php4food@xxxxxxxxx> wrote:
Okay I created a script that changes a basic smiley face into a red smiley face..but it doesn't replace all the yellow, it looks like a yellow shadow in the background:
<?php
$image = "smiley.png";
$data = getimagesize($image);
$width = intval($data[0]);
$height = intval($data[1]);
$cloneH = 0;
$hex = "FF0000";
$oldhex = "FCFF00";
$im = imagecreatefrompng($image);
$color = imagecolorallocate($im,hexdec(substr($hex,0,2)),hexdec (substr($hex,2,2)),hexdec(substr($hex,4,6)));
for($cloneH=0;$cloneH<$height;$cloneH++)
{
for($x=0;$x<$width;$x++)
{
if( colormatch($im,$x,$cloneH, $oldhex) )
imagesetpixel($im, $x, $cloneH, $color);
} }
header("Content-Type: {$data['mime']}");
imagepng($im);
function colormatch($image,$x,$y,$hex)
{
$rgb = imagecolorat($image,$x,$y);
$r = ($rgb >> 16) & 0xFF;
$g = ($rgb >> 8) & 0xFF;
$b = $rgb & 0xFF;
$r2 = hexdec(substr($hex,0,2));
$g2 = hexdec(substr($hex,2,2));
$b2 = hexdec(substr($hex,4,6));
if( $r == $r2 && $b == $b2 && $g == $g2 )
return true;
return false;
//echo "$r $r2, $g $g2, $b $b2";
}
?>
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Hi!
I have absolutely no clue if this will work. This has been typed directly into my mail client, so no guarantees.
<?php
function toRGB($color) {
return array('r' => ($color >> 16) & 0xFF, 'g' => ($color >> 8) & 0xFF, 'b' => $color & 0xFF);
}
function toColor($r, $g, $b) {
return $r * $g * $b;
}
$image = 'smiley.png';
list($w, $h) = getimagesize($image);
$im = imagecreatefrompng($image);
for ($y = 0; $y < $h; $y++) {
for ($x = 0; $x < $w; $x++) {
extract(toRGB(imagecolorat($im, $x, $y)));
if ($r >= 0xCC && $g >= 0xCC && $b <= 0x33)
imagesetpixel($im, $x, $y, toColor(($r + $g) / 2, 0, $b));
}
}
header('Content-type: image/png');
imagepng($im);
?>
:)
.
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