Re: [PHP] Function __call

thanks,

well, the 'new' woks the same with ou without '()' after class, I think...

and I now how it works, i only don't understand why... if the method
is not available outside of class it should go to __call function like
if it doesn't exist...
it doesn't make any sense to anyone else?


On Sat, Aug 30, 2008 at 2:38 PM, Jochem Maas <jochem@xxxxxxxxxxxxx> wrote:
Diogo Neves schreef:

hi all,

I'm sending this email only to ask if someone know if the works of
__call in private methods is bug or feature.

ex.

class user {
public function __call ( $name, $arguments ) {
do something
return call_user_func( array( $this, $name ), $arguments );

the fatal error occurs because the method exists, but it's
private ... __call() is only called if the method does not exist
at all:

class user {
public function __call($m, $a) {
if (is_callable(array($this, "_".$m)))
return $this->{"_".$m}( $a );
}

private function _xpto($a)
{
var_dump($a);
}
}

$u = new user;
$u->xpto(1, 2, 3);

}
private function xpto ( $arguments ) {
do something
}
}

new $user = new user();

the first 'new' is incorrect me thinks.

$user->xpto();

error:
Fatal error: Call to private method user::xpto() from context '' in
xpto.php on line 11

PS:
what a fucking I was thinking?

well, it don't have this public method, then it sholdn't know it
exists, then go to __call()
i really don't know if it make any sense to someone else, but it still
make sense to me

any thoughts?


---- ----
Thanks by your attention,

Diogo Neves
Developer @ Sapo.pt by PrimeIT.pt




---- ----
Thanks by your attention,

Diogo Neves
Developer @ Sapo.pt by PrimeIT.pt
.

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