Re: Continous Looping of a List

From: Paul Lalli (mritty_at_gmail.com)
Date: 09/25/04 

Date: Fri, 24 Sep 2004 19:41:43 -0400

cp wrote:

> My very bad. In my original problem statement, I neglected to mention
> that I need the loop to be continuous. So if the current selected id is
> 9, the functions needs to return 7 and 1. If the current selection is
> 1, it needs to return 9 and 3.
>

The output of my function is identical to the output of your funciton,
including returning the 2nd and last element when given the first. Can
you explain to me what your function does that mine does not?

Did you try to run my function, or are you just making an assumption it
doesn't do what you want?

> In article <KW_4d.173$va.125@trndny03>, Paul Lalli <mritty@gmail.com>
> wrote:
>
>>My version of your function:
>>
>>sub array_nav {
>> my ($val, @ids) = @_;
>> my $pos;
>> for ($pos=0; $pos<=$#ids; $pos++){
>> last if $val == $ids[$pos];
>> }
>> return undef unless $pos < @ids; #error checking
>
>
> Yes. I see what you are doing. however, I was hoping for error checking
> to determine whether the selected id was part of the set Before
> looping. May fault for not stating the problem more clearly.
>

The question here is "why?" Assuming you do have some sort of valid
reason for this, checkout the Perl FAQ:
perldoc -q contained

>
>> my $prev = $ids[$pos-1];
>> my $next = $pos == $#ids ? $ids[0] : $ids[$pos+1];
>> return ($prev, $next);
>>}

Paul Lalli

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