Re: substr forces scalar context with array argument

Andrew wrote:
> #-------------- output -------------------
>
> substr($s, $offset, $length) ---> acad
> substr($s, @tmp) ---> racadabra
> substr($s, @tmp[0,1]) ---> cadabra
> substr($s, $tmp[0], $tmp[1]) ---> acad
>
> #------------ end output ----------------
>
> ( Also, FWIW, using '@tmp[0,1]' yields a weird result I can't explain )

Didn't see this comment originally. The issue here is that a list
slice returns a list, not an array. A list in scalar context returns
the last item of that list. Therefore,
substr($s, @tmp[0,1]);
is equivalent to:
substr($s, 4);
since $tmp[1] == 4.

Paul Lalli

.

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