Re: split()'s pattern argument

Thanks David (and Xho),

Unfortunately I needed to do more than just split $_ on whitespace. I made
it work by calling split with the regex pattern that contained the scalar
and then simply checking the resultant list for a beginning NULL value. If
so, I just shifted to the next value and went on about my business. It
seems clug-eee to me, but it works and handles all of the test cases I've
thrown at it, so...

Thank y'all again.

Jerry

<usenet@xxxxxxxxxxxxxxx> wrote in message
news:1143752243.428795.257730@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Jerry Adair wrote:
to split(), it just so happens that the first line of data begins with a
space, followed by two "words" that are separated by whitespace. So the
list that I get back from split() has 3 elements in it

If all you want to do is split $_ on whitespace ignoring any leading
whitespace the you can simply say "split". Observe:

#!/usr/bin/perl

use warnings; use strict;

$_ = ' foo bar ';
my @array = split;

print map {"'$_'\n"} @array;

__END__


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