Re: accessing hash values with %hash->{foo} ?

Paul Lalli <mritty@xxxxxxxxx> wrote
which seems to suggest that the interpeter is allowing %hash->{foo} to
be syntactic sugar for $hash{foo}.

Does anyone know of a reason for this, or of a documentation that
mentions it?

Can't give you that, but JFYI:

phaylon@gaia:~/perl/plague> perl -wle'my %foo = ( bar => 23 ); print
%foo->{ bar }'
Using a hash as a reference is deprecated at -e line 1.
23
phaylon@gaia:~/perl/plague> perl -v

This is perl, v5.8.7 built for i686-linux-thread-multi
...


p


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