Problem with anonymous array in hash

Hello netties,

probably the solution is quite simple, but obviously I am blocked
currently concerning the following:

perl -e '@somearr=split(/ /,"11 12 13"); $hash{'array1'}->[0]=50;
$hash{'array1'}->[2]=100;printf("%d\n", scalar(@somearr));
printf("%d\n",
scalar(@$hash{'array1'}))'

Running this on the command line gives:

3
0

The first number is, as expected, the number of elements in the array
since evaluating an array in scalar context gives it's number of
elements. I would have expected "2" as the outcome for the second,
anonymous array stored in the hash, but obviously I am not referencing
to the array, or?

What am I doing wrong?

Cheers


Bernd

.

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