Re: Choosing the path based on the system "uname" command

On Feb 27, 2:49 pm, "doni" <doni.se...@xxxxxxxxx> wrote:
Hi,

I want to write a program that does check the appropriate system path
for perl in FreeBSD and Linux.

The path where I have it in FreeBSD is
#! /usr/local/bin/perl

and the path where it is in Linux is
#! /usr/bin/perl

I wanted the program to check for the uname of the system and choose
the appropriate path. Can anyone tell me how can I have my program
check this.

This is how I wrote the program but it doesnt work.

#! /usr/local/bin/perl

use strict;
use warnings;

if (system("uname") eq "Linux") {

What do you think that does?

Please read the documentation for the function you're using

perldoc -f system
perldoc -q system


#! /usr/bin/perl

That's a comment, and nothing more. The #! syntax means nothing
unless it's the first two characters of the file.

You probably meant to do an exec()

perldoc -f exec

And to avoid an infinite loop, you'll need to make sure you're not
already executing the version you meant to. I think you'll need both
the $0 and $^X variables. You can read about them in:
perldoc perlvar
In fact, you could probably get rid of the call to uname entirely, by
using the $^0 variable, also documented in that perldoc.

Hope that helps,
Paul Lalli

.

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