# Re: 12 hour clock and offset problem

*From*: anno4000@xxxxxxxxxxxxxxxxxxxxxx*Date*: 24 Jun 2007 11:25:46 GMT

Peter J. Holzer <hjp-usenet2@xxxxxx> wrote in comp.lang.perl.misc:

On 2007-06-23 22:59, anno4000@xxxxxxxxxxxxxxxxxxxxxx

<anno4000@xxxxxxxxxxxxxxxxxxxxxx> wrote:

Peter J. Holzer <hjp-usenet2@xxxxxx> wrote in comp.lang.perl.misc:

On 2007-06-18 11:03, anno4000@xxxxxxxxxxxxxxxxxxxxxx

<anno4000@xxxxxxxxxxxxxxxxxxxxxx> wrote:

The "x mod y" operation can be consistently defined for all real x and

y through

x mod y = x - y*floor(x/y) (y != 0)

y mod 0 = x

Ex falso quodlibet?

It is very customary to fix definitions when the original one

doesn't apply. Mathematicians do it all the time, provided that some

fundamental law(s) can be preserved by the fix.

But I think you mean:

x mod 0 = 0

No, I (or rather, Knuth and other Authors) mean

y mod 0 = x

What is x in this case? A random number? It doesn't appear on the left

side of the equation.

Oh dear. That's nonsense which I mindlessly repeated. I meant to say

x mod 0 = x

which is also what can be found in Knuth and other sources.

Anno

.

**References**:**12 hour clock and offset problem***From:*Kenetic

**Re: 12 hour clock and offset problem***From:*Peter J. Holzer

**Re: 12 hour clock and offset problem***From:*anno4000

**Re: 12 hour clock and offset problem***From:*Peter J. Holzer

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