Re: 12 hour clock and offset problem
 From: anno4000@xxxxxxxxxxxxxxxxxxxxxx
 Date: 24 Jun 2007 11:25:46 GMT
Peter J. Holzer <hjpusenet2@xxxxxx> wrote in comp.lang.perl.misc:
On 20070623 22:59, anno4000@xxxxxxxxxxxxxxxxxxxxxx
<anno4000@xxxxxxxxxxxxxxxxxxxxxx> wrote:
Peter J. Holzer <hjpusenet2@xxxxxx> wrote in comp.lang.perl.misc:
On 20070618 11:03, anno4000@xxxxxxxxxxxxxxxxxxxxxx
<anno4000@xxxxxxxxxxxxxxxxxxxxxx> wrote:
The "x mod y" operation can be consistently defined for all real x and
y through
x mod y = x  y*floor(x/y) (y != 0)
y mod 0 = x
Ex falso quodlibet?
It is very customary to fix definitions when the original one
doesn't apply. Mathematicians do it all the time, provided that some
fundamental law(s) can be preserved by the fix.
But I think you mean:
x mod 0 = 0
No, I (or rather, Knuth and other Authors) mean
y mod 0 = x
What is x in this case? A random number? It doesn't appear on the left
side of the equation.
Oh dear. That's nonsense which I mindlessly repeated. I meant to say
x mod 0 = x
which is also what can be found in Knuth and other sources.
Anno
.
 References:
 12 hour clock and offset problem
 From: Kenetic
 Re: 12 hour clock and offset problem
 From: Peter J. Holzer
 Re: 12 hour clock and offset problem
 From: anno4000
 Re: 12 hour clock and offset problem
 From: Peter J. Holzer
 12 hour clock and offset problem
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