Re: define an array in perl

jeniffer <zenith.of.perfection@xxxxxxxxx> wrote in comp.lang.perl.misc:
Hi
I am a newbie in perl. I have an array block_list :

push ( @block_list ,$word); # this word is read from a file.
$list_name = $block_list[$#block_list]; # i extract the last element

Why don't you use $word itself? If you still have the variable, there's
no need to access the array. If $word is no longer available, the
last element of an array is better accessed as

$block_list[-1];

ie $word in this case
now i want to define an array with the name $list_name


like ,
my @"$list_name";

Bad plan. You're aiming for symbolic references. See "perldoc -q
'variable as a variable name'" for why this is not a good idea.

But this is giving me errors...
sorry for the stupid question,,,please help me out ,,,,

Use a "hash of arrays" %h where the keys are the prospective variable
names and the values are references to the arrays. The array for
$list_name would be

@{ $h{ $list_name} }

and the $n-th element of that array can be accessed through

$h{ $list_name}->[ $n]

See "perldoc perldsc" and "perldoc perlreftut" for more on that.

Anno
.

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