Re: How can you embed a function inside a replacement operator ?

On Nov 27, 10:08 am, neilsolent <n...@xxxxxxxxxxxxxxxxxxxxxx> wrote:
Hi
Sorry if this is a basic question.
How can you embed a function inside a replacement operator ?

e.g.:
####################################
sub conv()
{
return $_[0] * 2;

}

$test = 'abc125abc';

$test =~ s/(\d+)/&conv($1)/g;

print $test . '\n';
####################################

The output of this script is:

abc&conv(123)abc

Whereas I would like it to be:

abc250abc


my $test = 'abc125def';
$test =~ s/(\d+)/conv($1)/ge;

print $test, "\n";

sub conv {
my ( $val ) = @_;
return $val * 2;
}


__OUTPUT__

bash-2.03$ ./replace_func.pl
abc250def
bash-2.03$
.

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