Re: Windows paths in glob



Gunnar Hjalmarsson <noreply@xxxxxxxxx> wrote in
news:65aa8vF2euim1U1@xxxxxxxxxxxxxxxxxx:

Dmitry wrote:
OK, so there's a well-known difficulty with handling Windows-style
paths in glob: it doesn't like backslashes, nor does it like spaces.
One solution to that is to use Unix-style paths:

glob('C:\Documents and Settings\*'); # Doesn't work
glob('C:/Documents\ and\ Settings/*'); # Works

Problem is, the rest of Perl's built-in file-handling functionality
behaves the other way around. For instance, with -d:

-d 'C:\Documents and Settings'; # Works
-d 'C:/Documents\ and\ Settings'; # Doesn't work

Question: is there any way to use the same path string with glob and
with the rest of Perl, without having to convert them back and forth?

A long time ago I decided to use opendir() and readdir() instead of
glob(). It may not be as 'elegant', but it works flawlessly without
escaping spaces.


OK, thanks. I guess if I wanted to process wildcards in the file name, I would pass them
through grep?
.



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