Re: using file globs and regex

OK - I figured it out - thanks.

This works fine: my($fn2) = grep ( $_ =~ '6' , glob 'f*');

What I'm confused about is the parens around the $fn2 ? Why are those
needed? Something tells me that has something to do with making the
scalar $fn2 into a list 'cause that's what grep returns, but i can't
remember what that's called to look it up.


On Aug 7, 1:23 pm, pgodfrin <pgodf...@xxxxxxxxx> wrote:
hmmm - what if I wanted to do some search on the glob?
like my($fn) = grep ( /5/ , glob 'f*');
On Aug 7, 12:23 pm, pgodfrin <pgodf...@xxxxxxxxx> wrote:

Thanks Tad - works like a charm...

On Aug 7, 12:06 pm, Tad J McClellan <ta...@xxxxxxxxxxxxxx> wrote:

pgodfrin <pgodf...@xxxxxxxxx> wrote:
This program works fine (with file names f1..f8 in the directory):

use warnings;
use strict;
    print "$_";
        my $fn=$_;
        print "File name $fn found..." and exit;

But I was hoping to be able to do something like:
my $fn=grep (/f5/,<f*>);

Basically just trying to have less lines of code...any suggestions?

use grep() in a list context instead of in a scalar context.

I don't like using overloaded angle brackets in my code.

If I want equality, I use an operator that tests for equality.

    my($fn) = grep ( $_ eq 'f5' , glob 'f*');

Tad McClellan
email: perl -le "print scalar reverse qq/moc.noitatibaher\100cmdat/"