Simple Regular Expression.

From: EFP (epridgett_at_woh.rr.com)
Date: 11/26/03

  • Next message: Gunnar Hjalmarsson: "Re: Simple Regular Expression." 
    Date: 26 Nov 2003 08:24:01 -0800

    Can anyone help me with a simple regular expression problem.

    All that I want to do is take a list of known data and extract a
    particular section of the string to form a new list.

    Here is my code snipet:

    my $fh = new FileHandle('c:\Units.txt') ; ## sucks up my work file
    my @lines1 = <$fh>; ## assigns the filehandler contents to @lines1
    foreach $string (@lines1) ## extract each line from @lines and put it
    in $string
    {

    $string =~ m/\*@@\$/;

    print "NewString :: $string\n";
    }

    Sample Units.txt data:
    .\Source\CPP\ConnPool\src\oraUtils.pc@@
    .\Source\CPP\ConnPool\src\sample.pc@@
    .\Source\CPP\Services\src\OExceptServer.pc@@
    .\Source\CPP\Services\src\Rees1440Server.pc@@
    .\Source\CPP\Services\src\SWDTestServer.pc@@
    .\Source\CPP\TestCases\TestRees1800\testRees1800Cursor.pc@@
    .\Source\CPP\TSRI\Remis1\cxxsrc\Buffer_Area.pc@@

    I just want the:
    oraUtils.pc

    I'd even settle for:
    oraUtils.pc@@

    So basically I want the contents between "\" and the "@@"

    I thought that:
    $string =~ m/\*@@\$/;

    Would go to the end of the search line and find "@@" and get anything
    "*" between the "@@" and the "\" and set $string to this new value.

    What it returns is:
    element:: .\Source\CPP\ConnPool\src\oraUtils.pc@@

    Can anyone correct my understanding of regular expression and
    assignment to a varibale.

    Thanks.
    EFP

  • Next message: Gunnar Hjalmarsson: "Re: Simple Regular Expression."

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