How to write a page break character.
From: Chetak Sasalu (chetak.sasalu_at_wipro.com)
Date: 12/20/03
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Date: Sat, 20 Dec 2003 13:07:18 +0530 To: <ajey@pdx.edu>
Hi,
I want to search for the word "status" in a group of files in a
directory and replace it with "status\n^L" where ^L is a page break
chatacter, In vi I can type it in using cntrl+l.
I want to do this by
perl -p -i.old -e 's/^STATUS$/STATUS\n(page break character)/' *
How can I "write" the page break character (^L) on command line?
Thanks,
Chetak
-----Original Message-----
From: Ajey [mailto:ajey@pdx.edu]
Sent: Saturday, December 20, 2003 7:43 PM
To: Douglas Lentz
Cc: David Inglis; beginners@perl.org
Subject: Re: how to remove a ^M charaters from a variable
if its a unix file,.open in vi
:%s/ctrl+v ctrl+m//g
(where ctrl+v and ctrl+m gives the ^M character.)
cheers
On Fri, 19 Dec 2003, Douglas Lentz wrote:
> David Inglis wrote:
>
> >I am reading in a csv file and it has a control character ^M at the
> >end of each line how can I remove these charaters, I have tried the
> >following and had no success.
> >
> >$a=~s/\^M//;
> >$a=~s/^M//;
> >
> >
> >Any help appreciated thanks.
> >
> >
> >
> >
> This is an MS-DOSsy file, where each line is terminated by the famous
> CR/LF combination. "^M" is the carriage return. Between the regex
> slashes ("the jungle") "^" means "beginning of line", so what you have
> instructed regex to do is erase any capital "M" that happens to occur
at
> the beginning of a line.
>
> If you have a copy of the program dos2unix around, it will take care
> of
> this for you, otherwise you can try $a =~ s/\x0D//;
>
> which means replace any CR you find with null. HTH.
>
>
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