Perl Class simple problem

From: Graeme McLaren (iamnotregistered_at_hotmail.com)
Date: 05/29/04

  • Next message: Randal L. Schwartz: "Re: The >> operator" 
    To: beginners@perl.org
Date: Sat, 29 May 2004 13:10:12 +0100

    Afternoon all, I'm trying to write a class for configuration values for
    different sites so that they can use the same conf class, then create an
    object and get whatever value they need.

    The problem I have this:

    I create an object and pass a value to my constructor like this:
    Conf->new(site=>'x'), this tells the constructor which site I want the
    config for, then at the end of the constructor I call $self->_init();
    This passes a reference to $self ( I think ) using $self = shift; When I
    die out using: die %{$self};
    I get the value that "x" equals ( x => '/usr/local/apache/htdocs/x' ) I
    need to perform additional logic in $self->_init(); and what I really need
    to do is get the name, which in this case is "x" instead of the value which
    in this case is "/usr/local/apache/htdocs/x". How do I do this I'm a bit
    lost with perl OO programming :(

    Thank you for any light anyone can shed on this.

    Graeme :)

    ################ Perl Code #################

    sub new{
        my ($caller, %arg) = @_;
        my $conv = {
          x => '/usr/local/apache/htdocs/x',
          y => '/usr/local/apache/htdocs/y',
          z => '/usr/local/apache/htdocs/z'
        };
        my $caller_is_obj = ref($caller);
        my $class = $caller_is_obj || $caller;
        my $self = bless {}, $class;
        $self->{_doc_root} = $conv->{$arg{site}||'x'};
        if(!exists $conv->{$arg{site}}){
           die "check for typos in yer params";
        }
        $self->_init();
    }

    sub _init{
      my $self = shift;
      die %{$self};
    }
    ##################### End of Perl Code ####################

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  • Next message: Randal L. Schwartz: "Re: The >> operator"

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