RE: How to store the out put in StringBuffer
From: Sreedhar Kalkunte-Venkatachala (Sreedhar.Kalkunte-Venkatachala_at_ubs.com)
Date: 10/24/04
- Next message: Kevin Pfeiffer: "charset problem using HTTP::Request on command line"
- Previous message: mk76_at_buffalo.edu: "Re: perl-cgi"
- Maybe in reply to: Sreedhar Kalkunte-Venkatachala: "How to store the out put in StringBuffer"
- Messages sorted by: [ date ] [ thread ] [ subject ] [ author ]
Date: Sun, 24 Oct 2004 11:17:31 +0100 To: <zeus.odin@verizon.net>, <beginners@perl.org>
Hi
thanks. problem resolved
I have added variable called $msg1.=$previousline;
Regards
Sreedhar
-----Original Message-----
From: Zeus Odin [ mailto:zeus.odin@verizon.net]
Sent: 23 October 2004 22:40
To: Kalkunte-Venkatachala, Sreedhar; beginners@perl.org
Subject: RE: How to store the out put in StringBuffer
The following should do what you want. @print is an array of array
references. You have to read the documentation, learn what it is, and how to
use it. Now would be a good time to learn the Perl debugger so you can step
through my code. Your assignment is to print @print in your DoChat()
routine. (After all, I can't very well write the whole thing for you)
;-)
@print is the buffer you keep referring to:
-------------------
#!/usr/bin/perl
use warnings;
use strict;
my(@tail, @print);
open LOG, 'mastering.txt' or die "Could not open log file: $!";
while (<LOG>) {
push @tail, $_;
shift @tail if @tail > 10;
if (/error/) {
my($line);
for (1 .. 10) {
push @tail, $line if defined($line = <LOG>);
}
push @print, [ @tail ];
@tail = ();
}
}
DoChat()
-------------------
Good luck,
ZO
-----Original Message-----
From: Sreedhar.Kalkunte-Venkatachala@ubs.com
[ mailto:Sreedhar.Kalkunte-Venkatachala@ubs.com]
Sent: Saturday, October 23, 2004 12:38 PM
To: zeus.odin@verizon.net
Subject: RE: How to store the out put in StringBuffer
Hi
Thank you very much for the mail.
Say in the for loop it is printing
var1 --> 1
var2 --> 2
var3 --> 3
var4 --> 4
var5 --> 5
var6 --> 6
How to store var1,2,3,4,5,6 to one variable --> $Newvar should print
1
2
3
4
5
6
A buffer kind
i.e 6 lines is should store in one variable. Am I asking some thing wrong
regards
Sreedhar
-- To unsubscribe, e-mail: beginners-unsubscribe@perl.org For additional commands, e-mail: beginners-help@perl.org < http://learn.perl.org/> < http://learn.perl.org/first-response> Visit our website at http://www.ubs.com This message contains confidential information and is intended only for the individual named. If you are not the named addressee you should not disseminate, distribute or copy this e-mail. Please notify the sender immediately by e-mail if you have received this e-mail by mistake and delete this e-mail from your system. E-mail transmission cannot be guaranteed to be secure or error-free as information could be intercepted, corrupted, lost, destroyed, arrive late or incomplete, or contain viruses. The sender therefore does not accept liability for any errors or omissions in the contents of this message which arise as a result of e-mail transmission. If verification is required please request a hard-copy version. This message is provided for informational purposes and should not be construed as a solicitation or offer to buy or sell any securities or related financial instruments.
- Next message: Kevin Pfeiffer: "charset problem using HTTP::Request on command line"
- Previous message: mk76_at_buffalo.edu: "Re: perl-cgi"
- Maybe in reply to: Sreedhar Kalkunte-Venkatachala: "How to store the out put in StringBuffer"
- Messages sorted by: [ date ] [ thread ] [ subject ] [ author ]
Relevant Pages
|