Re: interpoliation within regexp

On 09/28/2006 08:16 AM, Derek B. Smith wrote:
--- "Derek B. Smith" <derekbellnersmith@xxxxxxxxx>
wrote:

I need to substitute a conversion using chr, but
have
failed on multiple attempts. Basically if the first
element contains a # then convert it. Will anyone
advise?

thank you
derek

#if first char is a-z then print it else warn
#chop string into individual characters

my @chars = unpack
("A1" x length($password),$password);

if ($chars[0] =~ /^\D/) {
print "Your new string is:\t",@chars,"\n";
}
else {
print "string starts with number, now
converting\n",
@chars, "\n";
substr($chars[0],0,1) =~
s/\Q{$chars[0]}/{chr($chars[0]}\E/;
print @chars;
}


I will try to use the /e modifier as such:

s/(\$\w+)/$1/e;

An explanation is below:
/e
Righthand side of a s/// is code to eval
/ee
Righthand side of a s/// is a string to eval, then
run as code, and its return value eval'led again.



What does your input data look like, and what do you want the output to look like?


.

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