RE: String Manipulation

But in this case it was also not needed as I replied without actually
reading the requirements.

-----Original Message-----
From: Paul Lalli [mailto:mritty@xxxxxxxxx]
Sent: 31 July 2007 14:21
To: beginners@xxxxxxxx
Subject: Re: String Manipulation

On Jul 31, 8:40 am, dharshana...@xxxxxxxxx (Dharshana Eswaran) wrote:
And your suggestion worked. Thank you. But in the string which u had
suggested, [,\s*\/*]?, here \s* => tells spaces are optional,

No it doesn't. The "dirty dozen" characters lose their special meaning
inside of a character class.

/\* tells the beginning of the comment,

That's not what's in the pattern, and it wouldn't be correct even if it was.
The characters are \/*, not /\*. The first is an escaped slash follwed by
an asterisk, the second is a slash followed by an
escaped asterisk. The slash is still special because it's the regexp
delimiter, and so needs to be escaped. Your changing it is a syntax error.

I am unable to understand what these in a square bracket along with a
? mean?

The square brackets are a character class. Essentially, a list of options.
[,\s*\/*]?
means "0 or 1 of either a comma, a space, an asterisk, a slash, or an
asterisk". Obviously, the two asterisks are redundant.

You should freshen up on regular expressions:
perldoc perlreref
perldoc perlretut
perldoc perlre

Paul Lalli


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