How to match a token not be quoted?

Hello,
I want to a cure regex that match following requirements: given $line =
'abc abc "abc abcc" abcc', I want to replace all instances of "abc" that
not in quotation with, say 'd', so I expect I get 'd d "abc abcc" dc'.
What should I write my regex? I try some and referred cook book also, no
solution. Thanks in advance.


Best regards,
Bingfeng



Relevant Pages

  • Re: How to match a token not be quoted?
    ... Zhao, Bingfeng wrote: ... I want to a cure regex that match following requirements: ... not in quotation with, say 'd', so I expect I get 'd d "abc abcc" dc'. ...
    (perl.beginners)
  • Re: How to match a token not be quoted?
    ... Zhao, Bingfeng wrote: ... not in quotation with, say 'd', so I expect I get 'd d "abc abcc" dc'. ... Gunnar Hjalmarsson ...
    (perl.beginners)
  • Re: How to match a token not be quoted?
    ... Zhao, Bingfeng wrote: ... not in quotation with, say 'd', so I expect I get 'd d "abc abcc" dc'. ... What should I write my regex? ...
    (perl.beginners)