Re: How to match a token not be quoted?

Rob Dixon wrote:
Gunnar Hjalmarsson wrote:
Zhao, Bingfeng wrote:
I want to a cure regex that match following requirements: given $line =
'abc abc "abc abcc" abcc', I want to replace all instances of "abc" that
not in quotation with, say 'd', so I expect I get 'd d "abc abcc" dc'.

$line =~ s/("[^"]*")|abc/$1 ? $1 : 'd'/eg;

You need a non-greedy modifier on that Gunnar:

$line =~ s/("[^"]*?")|abc/$1 ? $1 : 'd'/eg;

Why would I need that? Are you mixing up [^"]* with .* ?

--
Gunnar Hjalmarsson
Email: http://www.gunnar.cc/cgi-bin/contact.pl
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