Re: Integer_division/3....stuck on the recursion part.
- From: "Pierpaolo BERNARDI" <olopierpa@xxxxxxxxx>
- Date: 27 Nov 2005 19:07:47 -0800
sikkwanchu@xxxxxxxxxxx wrote:
> integer_division(_X,0,error).
>
> integer_division(0,_,_).
?
> integer_division(X,Y,Z):-
> X >= Y,
> N is X - Y,
> integer_division(N,Y,A),
> Z = A + 1.
>
> im stuck in where the recurison ends.
What's the result when X < Y ?
Just add a clause which covers this case.
P.
.
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