Re: Replace occurrence of a list with another?
- From: Bill Spight <bspight@xxxxxxxxxxxx>
- Date: Wed, 26 Apr 2006 01:12:02 GMT
Dear Brian,
That is the stop condition for the replaceall predicate.
Sorry, I meant this clause.
replaceall(X,Y,[H|T],[H|List]) :-
replaceall(X,Y,T,List).
What does it say?
Best,
Bill
.
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