Hi,
how about this :
X = [[[a,b],[b,c]],[[c,d],[d,v]]],
flatten(X,Y),
sort(Y,Z).
Regards
Thorsten
phantastic@xxxxxxxxxx wrote:
Hi,
I have a list like this: [[[a,b],[b,c]],[[c,d],[d,v]]] where the
number of elements (sublists) is two but number of elements inside
sublist can be random.
I want a list like this: [[a,b,c], [c,d,v]] (in this case)
I have considered union/3 predicate but I don't know how I can iterate
on every member of the list.
Any help?
Re: Iterative union ... number of elements (sublists) is two but number of elements inside ... I have considered union/3 predicate but I don't know how I can iterate... on every member of the list. ... (comp.lang.prolog)
Re: Iterative union ... number of elements (sublists) is two but number of elements inside ... Your list contains 2 sublists, which contain 2 subsublists each, which ... I have considered union/3 predicate but I don't know how I can iterate... on every member of the list. ... (comp.lang.prolog)
Iterative union ... number of elements (sublists) is two but number of elements inside ... I have considered union/3 predicate but I don't know how I can iterate... on every member of the list. ... (comp.lang.prolog)
Re: Iterative union ... number of elements (sublists) is two but number of elements inside ... I have considered union/3 predicate but I don't know how I can iterate... on every member of the list. ... (comp.lang.prolog)
Re: mErge ...student wrote: ... every member of A is a member of B but there are at least two members of A occur in different order in B, ... These answers satisfy the "has each of the given lists as ...sublists" part of my definition but not the ... (comp.lang.prolog)
