Re: yield_all needed in Python

From: Douglas Alan (nessus_at_mit.edu)
Date: 03/02/05 

Date: Tue, 01 Mar 2005 23:50:20 -0500

Isaac To <isaact@outblaze.com> writes:

>>>>>> "Isaac" == Isaac To <iketo2@netscape.net> writes:
>
> def gen_all(gen):
> for e in gen:
> yield e
>
> def foogen(arg1):
> def foogen1(arg2):
> # Some code here
> # Some code here
> gen_all(arg3)
> ^ I mean foogen1(arg3), obviously, and similar for below
> # Some code here
> gen_all(arg4)
> # Some code here
> gen_all(arg5)
> # Some code here
> gen_all(arg6)
>
> Regards,
> Isaac.

If you actually try doing this, you will see why I want "yield_all".

|>oug

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