Re: change vars in place w/loop or list comprehension
- From: Jatinder Singh <jatinder@xxxxxxxxxxxxxxxxxxxx>
- Date: Tue, 31 May 2005 08:09:16 -0500
Hi
what u can do over here is
add a,b,c... in a list e.g. list.append(vars..)
and then use the statement
newlist = map(lambda x:x.upper(),list)
Now ur newlist will contain the modified list.
HOPE THIS THE BETTER SOLUTION TO UR PROBLEM
Quoting ken.boss@xxxxxxxxxxxxxxx:
> I am a python newbie, and am grappling with a fundamental concept. I
> want to
> modify a bunch of variables in place. Consider the following:
>
> >>> a = 'one'
> >>> b = 'two'
> >>> c = 'three'
> >>> list = [a, b, c]
> >>> for i in range(len(list)):
> ... list[i] = list[i].upper()
> ...
> >>> [a, b, c] = list
> >>> a
> 'ONE'
>
> or, better:
>
> >>> a = 'one'
> >>> b = 'two'
> >>> c = 'three'
> >>> [a, b, c] = [s.upper() for s in [a, b, c]]
> >>> a
> 'ONE'
>
> Both of these accomplish what I'm after; I prefer the second for its
> brevity.
> But either approach requires that I spell out my list of vars-to-alter
> [a, b, c] twice. This strikes me as awkward, and would be difficult
> with longer lists. Any suggestions for a better way to do this?
>
> --Ken
>
> --
> http://mail.python.org/mailman/listinfo/python-list
>
--
Regards,
Jatinder Singh
? Everyone needs to be loved... especially when they do not deserve it.?
.
- References:
- change vars in place w/loop or list comprehension
- From: ken . boss
- change vars in place w/loop or list comprehension
- Prev by Date: Re: Newbie Here
- Next by Date: Re: exit after process exit
- Previous by thread: change vars in place w/loop or list comprehension
- Next by thread: Re: change vars in place w/loop or list comprehension
- Index(es):
Relevant Pages
|
