Re: comple list slices

Although I don't know if this is faster or more efficient than your
current solution, it does look cooler:

def grouprows(inrows):
rows = []
rows[:] = inrows # makes a copy because we're going to be
deleting
while len(rows) > 0:
rowspan = rows[0]["rowspan"]
yield rows[0:rowspan] # "returns" this value, but control flow
unaffected
del rows[0:rowspan] # remove what we just returned from the
list, and loop

grouper = grouprows(copyrows)
print [x for x in grouper]

This is basically just a simple function that rips chunks off the front
of a list and returns them. Because the function uses "yield" rather
than "return," it becomes a generator, which can be treated by Python
as an iterator.

.