Re: help with a function
- From: Ben Finney <bignose+hates-spam@xxxxxxxxxxxxxxx>
- Date: Wed, 17 May 2006 12:28:56 +1000
Lance Hoffmeyer <lance@xxxxxxxxxxxxxx> writes:
def even_odd_round(num):
if(round(num,2) + .5 == int(round(num,2)) + 1):
if(int(num,0) % 2): #an odd number
rounded_num = round(num,2) + .1
else: #an even number
rounded_num = round(num,2) - .1
rounded_num = int(rounded_num)
return rounded_num
even_odd_round(5.5)
Traceback (most recent call last):
File "<interactive input>", line 1, in ?
File "<interactive input>", line 3, in even_odd_round
TypeError: int() can't convert non-string with explicit base
Two problems.
One is the simple fact reported by the error message: you're
attempting to specify that a number object (already represented inside
Python as a number) should be converted using a particular base. (Why
you've chosen 0 as the base is beyond me.)
That only makes sense with a string of digit characters, where Python
needs to be told what numeric base each digit is (decimal, octal,
hexadecimal, whatever). It makes no sense for objects that are already
numbers, since they're not represented as digits in a base.
The other problem is specifying a base at all. Why not just convert
the object to an int using the default base?
If you're confused about how built-in types or functions work, you
should become familiar with the help system in the interpreter:
help(int)
--
\ "Any sufficiently advanced bug is indistinguishable from a |
`\ feature." -- Rich Kulawiec |
_o__) |
Ben Finney
.
- References:
- help with a function
- From: Lance Hoffmeyer
- help with a function
- Prev by Date: Re: A Unicode problem -HELP
- Next by Date: Re: help with a function
- Previous by thread: help with a function
- Next by thread: Re: help with a function
- Index(es):
Relevant Pages
|
