Re: self question


Schüle Daniel wrote:
Hi all,

given python description below

import random

class Node:
def __init__(self):
self.nachbarn = []

class Graph(object):
# more code here
def randomizeEdges(self, low=1, high=self.n):
pass


graph = Graph(20)
graph.randomizeEdges(2,5)

I am burned by high=self.n
quick test with

cnt = 1
def foo():
global cnt
cnt += 1
return cnt

def bar(x=foo()):
print x

bar() # 2
bar() # 2
bar() # 2

this is not behaviour C++ programmer would expect
does someone know why this kind of behaviour is/was choosen?

Regards, Daniel

I think the answer is that 'def' is an executable statement in python
rather than a definition that the compiler interprets at compile time.

As a result the compiler can evaluate 'foo()' when it defines 'bar', so
it does.

The following works as expected:
def bar():
print foo()

Hopefully somebody more knowledgable will also respond

.

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