Re: class declaration shortcut

Luis M. González a écrit :
I've come across a code snippet in www.rubyclr.com where they show how
easy it is to declare a class compared to equivalent code in c#.
I wonder if there is any way to emulate this in Python.

The code is as follows:

Person = struct.new( :name, :birthday, :children)

s/struct/Struct/

I tried something like this, but it's nothing close to what I'd like:

def klass(table, *args):
cls = new.classobj(table, (), {})
for i in args:
setattr(cls, i, i)
return cls

But this above is not what I want.
I guess I should find a way to include the constructor code inside
this function, but I don't know if this is possible.
Also, I wonder if there is a way to use the variable name in order to
create a class with the same name (as in "Person"above).

Well, if anyone has an idea, I'd like to know...

Here's a *very* Q&D attempt - that doesn't solve the name problem:
def Struct(name, *attribs):
args = ", ".join("%s=None" % attr for attr in attribs)
body = "\n ".join("self.%s = %s" % (attr, attr) \
for attr in attribs)
source = ("""
class %s(object):
def __init__(self, %s):
%s
""".strip()) % (name, args, body)
#print source
code = compile(source, 'dummy', 'single')
exec code
return locals()[name]

But note that I'd immediatly fire anyone using such an abomination in production code.

.

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