Re: How can I programmatically find the name of a method from within that method?

Tony wrote:

Is this cheating?

Isn't it harder to calculate the magic indices than just writing down the
names twice?

class a:
        def square(self, x):
                print 'executing:', dir(self)[-1]
                print x*x
        def cube(self, x):
                print 'executing:',     dir(self)[-2]
                print x*x*x

b=a()
b.square(3)
b.cube(3)
Output:

PyMate r6780 running Python 2.3.5 (python)
function self naming2.py

executing: square
9
executing: cube
27

Is this cheating?

No, just wrong.

class A:
.... def alpha(self): return dir(self)[-2]
.... def gamma(self): return dir(self)[-1]
....
a = A()
a.alpha(), a.gamma()
('alpha', 'gamma')
a.beta = 42
a.alpha(), a.gamma()
('beta', 'gamma')

Peter
.

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