Re: 3 number and dot..

On Oct 31, 10:50 pm, Roberto Bonvallet <rbonv...@xxxxxxxxx> wrote:
On 31 oct, 16:58, Abandoned <best...@xxxxxxxxx> wrote:



Hi..
I want to do this:
for examle:
12332321 ==> 12.332.321

How can i do?
x = 12332321
'.'.join(''.join(i for n, i in g) for k, g in groupby(enumerate(reversed(str(x))), lambda (n, i): n//3))[::-1]
'12.332.321'

--
Roberto Bonvallet

Thank you but it give me this error:
NameError: name 'groupby' is not defined

.

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