Re: Sorting a list depending of the indexes of another sorted list

On Mon, 21 Jan 2008 17:32:42 +0800, J. Peng wrote:

Steven D'Aprano 写道:
On Mon, 21 Jan 2008 16:23:50 +0800, J. Peng wrote:

J. Peng 写道:

k = (i.split())[3]
y = (i.split())[1]
btw, why can't I write the above two into one statement?

(k,y) = (i.split())[3,1]

I don't know. What's "i"?

I'm guessing "i" is a string (and what a horrible choice of a name for
a string!) So i.split() will return a list. List indexing with multiple
arguments isn't defined, which is why you can't write

k, y = (i.split())[3,1]


Thanks.
Then one have to split the list twice.Given the list is large,it's maybe
not good for performance.Is it a more effective split way?

Yes, split the string once and store it.

words = "Nobody expects the Spanish Inquisition!"
alist = words.split()
k = alist[3] # "Spanish"
y = alist[1] # "expects"



--
Steven
.

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