Re: small problem with re.sub
- From: "Mark Tolonen" <mark.e.tolonen@xxxxxxxxxxxxxx>
- Date: Wed, 30 Jan 2008 19:43:05 -0800
"Astan Chee" <stanc@xxxxxxxxx> wrote in message news:mailman.78.1201748496.9267.python-list@xxxxxxxxxxxxx
Hi,
I have a html text stored as a string. Now I want to go through this string and find all 6 digit numbers and make links from them.
Im using re.sub and for some reason its not picking up the previously matched condition. Am I doing something wrong? This is what my code looks like:
htmlStr = re.sub('(?P<id>\d{6})','<a href=\"http://linky.com/(?P=id).html\">(?P=id)</a>',htmlStr)
It seems that it replaces it alright, but it replaces it literally. Am I not escaping certain characters?
Thanks again for the help.
Cheers
Animal Logic
http://www.animallogic.com
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See the help for re.sub: "Backreferences, such as "\6", are replaced with the substring matched by group 6 in the pattern."
This should work:
htmlStr = re.sub('(?P<id>\d{6})','<a href="http://linky.com/\\1.html">\\1</a>',htmlStr)
--Mark
.
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