Re: list traversal and remove

On Jan 31, 7:49 am, "digisat...@xxxxxxxxx" <digisat...@xxxxxxxxx>
wrote:
I supposed the below code will print seven 2 and generate the list li
without 2.
Strangely it only print  four 2. If you change the number of 2 in the
list, the results are all beyond expectation.
I know the other way to achieve the expected goal, but why this is
happening? Could somebody enlight me?

li= [2,2,2,2,2,2,2,3,4,5,6,7,8,9]
for x in li:
    if x == 2:
        print x
        li.remove(x)

There's just been a thread on this:

http://groups.google.com/group/comp.lang.python/browse_thread/thread/290623baaa46e72a/

--
Arnaud
.