Re: How to covert ASCII to integer in Python?
- From: Mensanator <mensanator@xxxxxxx>
- Date: Fri, 30 May 2008 08:41:16 -0700 (PDT)
On May 30, 10:03�am, Philipp Pagel <pDOTpa...@xxxxxxxxxxxxxxxxxxxxx>
wrote:
Skonieczny, Chris <Skonieczn...@xxxxxxxxxxxxx> wrote:
YOU SHOULD REMOVE or CORRECT YOUR POST here:
http://mail.python.org/pipermail/python-list/2007-February/427841.html�;
It is not true - eg. try :
a='P' � � � � � �# P is ASCII , isn't it ?
b=int(a)
and what you will get ? An error !!!
'P' is obviously not an ASCII representation of a number.
It is in base 36.
25a='P'
b=int(a,36)
b
What did you expect? The closest number by visual appearance?
cu
� � � � Philipp
--
Dr. Philipp Pagel
Lehrstuhl f. Genomorientierte Bioinformatik
Technische Universit�t M�nchenhttp://mips.gsf.de/staff/pagel
.
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