Re: How to covert ASCII to integer in Python?

On May 30, 7:59 pm, Mensanator <mensana...@xxxxxxx> wrote:
On May 30, 6:44 pm, Joshua Kugler <jkug...@xxxxxxxxxxx> wrote:





Skonieczny, Chris wrote:
YOU SHOULD REMOVE or CORRECT YOUR POST here:
http://mail.python.org/pipermail/python-list/2007-February/427841.html

It is not true - eg. try :
a='P'            # P is ASCII , isn't it ?
b=int(a)
and what you will get ? An error !!!

Or probably you yourself should - quote :
"You probably should go through the tutorial ASAP that is located here:

http://docs.python.org/tut/";

int() converts a strings that is a valid intenter.  What you're looking for
is ord().

Possibly. Perhaps the OP wants the position of 'P'
in the alphabet, in which case he wants b=64-ord(a)
or b=16.

Oops! I meant ord(a)-64, of course.






In [1]: ord('d')
Out[1]: 100

In [2]: a='P'

In [3]: b=ord(a)

In [4]: b
Out[4]: 80

j
.