Re: problems with opening files due to file's path

On 2008-06-11, Alexnb <alexnbryan@xxxxxxxxx> wrote:

I am using GUI, Tkinter to be exact. But regardless of how the
path gets there, it needs to opened correctly. The problem I
am running into is that the program receives a path of a file,
either .wma or .mp3 and is supposed to open it. I run into
problems when there is either a ")" or a number next to the
backslash "\" in the file path. I am looking for a way to make
it work with a variable, I can make it work when I physically
type it in, but not with a variable that holds the path.

You're going to have to show us code and example input and
output. Your description of the problem is far too vague for
anybody to help you.

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