Re: Getting sorting order


"leodp" <leodp@xxxxxxxxx> wrote in message news:d1014b7c-226f-4093-b712-a41a49c4e7d9@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

Or provide a better explanation and an example. Do you mean something like
this?


Hi Peter,
a small example:

master=[1,4,3,2]
slave1=['d','c','b','a']
slave2=[1,2,3,4]

master.sort() # this is ok, but does not return infos on how the list
was sorted
slave1.sort(key=_maybe_something_here_referring_to_master_)
slave2.sort(key=_maybe_something_here_referring_to_master_)

Then I should get:
master=[1,2,3,4]
slave1=['d','a','b','c']
slave2=[1,4,3,2]


Hope it is more clear now.
Thanks, leodp

How about:

master=[1,4,3,2]
slave1='d c b a'.split()
slave2=[1,2,3,4]
x=zip(master,slave1,slave2)
x.sort()
master,slave1,slave2=zip(*x)
master
(1, 2, 3, 4)
slave1
('d', 'a', 'b', 'c')
slave2
(1, 4, 3, 2)

--Mark

.