Re: common elements between list of lists and lists
- From: Bighead <Xue.Huichao@xxxxxxxxx>
- Date: Thu, 17 Jul 2008 02:19:46 -0700 (PDT)
On Jul 17, 4:30 pm, antar2 <desoth...@xxxxxxxxx> wrote:
Hello,
I am a beginner in python.
following program prints the second element in list of lists 4 for the
first elements in list 4 that are common with the elements in list 5
list4 = [['1', 'a'],['4', 'd'],['8', 'g']]
list5 = ['1', '2', '3']
for j in list4:
for k in list5:
if j[0] == k:
print j[1]
Result: a
I would like to do the same thing starting with following lists, where
the numbers in list 5 are without ''. Is there a way to convert
integers in a list to integers in '' ? This is based on a situation
where I want to find common numbers between a list and a list of lists
where the numbers in the list are without '' and the numbers in the
list of lists are with ''
list4 = [['1', 'a'],['4', 'd'],['8', 'g']]
list5 = [1, 2, 3]
This might be a stupid question, but anyway, thanks for your answer
It is not my first post on this site. In some way it is not possible
to react on the messages that I receive to thank the persons that
react. Anyway, thanks a lot
By "integer without ''" you mean integers not embraced by single
quotes, right?
Actually, '1' is a string, not an integer. If you want to normalize
the first elements of all the lists in list4, just use int() to
convert them.
That is:
list4 = [['1', 'a'],['4', 'd'],['8', 'g']]
list5 = ['1', '2', '3']
set5 = set(map(int, list5))
list4 = [[int(i[0]), i[1]] for i in list4]
for j in list4:
if j[0] in set5: print j[1]
You can have a try :)
.
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- From: antar2
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