Re: how to convert '\xf0' to 0xf0 ?

Looks like you need the struct module. That can convert binary fields of
various lengths into the appropriate Python types, and vice versa.

import struct
struct.unpack("L", '\xf0\xf0\xff\xfe')
(4278186224L,)
struct.unpack("l", '\xf0\xf0\xff\xfe')
(-16781072,)


regards
Steve

chengang.beijing@xxxxxxxxx wrote:
Hi,

ord('\xf0') works and it only works for char. Do you know any way to
convet
'\xf0\xf0' and '\xf0\xf0\xff\xfe' to integer?


Br, Chen Gang

On Dec 12, 12:40 pm, Steve Holden <st...@xxxxxxxxxxxxx> wrote:
chengang.beij...@xxxxxxxxx wrote:
'\xf0' is the value read from a binary file, I need to change this
kinds strings to int for further processing...
if it is in C, then '\xf0' is an integer and it can be handled
directly, but in python, it is a string.
and both int('10',16) and int('0x10',16) returns 16.
Br, Chen Gang
On Dec 12, 12:06 pm, Tommy Nordgren <tommy.nordg...@xxxxxxxxx> wrote:
On Dec 12, 2008, at 4:48 AM, chengang.beij...@xxxxxxxxx wrote:
int('\xf0',16) doesn't work, any way to do that?
--
http://mail.python.org/mailman/listinfo/python-list
Should be int('10',16)
or int('0x10',16)
It seems that you want the integer value of a character you read in from
a file. Is this correct? Note that '\xf0' is the interpreter's way of
representing a one-character string whose only character has the
hexadecimal value f0, because the actual character is not printable: the
backslash has a special meaning in character string literals.

Any one-character string, however, can be converted to the equivalent
integer value using the ord() function. You can convert the other way
using the chr() function:



ord('A')
65
chr(65)
'A'
ord('\xf0')
240
chr(240)
'\xf0'
hex(240)
'0xf0'

So just apply the ord() function to the character and you'll get its
integer value!

regards
Steve
--
Steve Holden +1 571 484 6266 +1 800 494 3119
Holden Web LLC http://www.holdenweb.com/

--
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--
Steve Holden +1 571 484 6266 +1 800 494 3119
Holden Web LLC http://www.holdenweb.com/

.

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