Re: Change one list item in place

Gnarlodious wrote:
On Dec 1, 6:23 am, Jean-Michel Pichavant <jeanmic...@xxxxxxxxxxx>
wrote:
what about

def query():
return ["Formating only {0} into a string".format(sendList()[0])] +
sendList()[1:]

However this solution calls sendList() twice, which is too processor
intensive.

You got to get rid of those nerd habits of unecessary optimization. To put it simple, you just don't give a [put whatever suitable word] to the overhead of 2 calls of sendList instead of one.
Until query is called a million time a second, there's no need to sacrifice anything on the optimization altar, because no one will never ever see the difference.

You can find my solution not that readable, that would be a proper reason for not using it. It's up to you.

JM






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