Re: what does 'a=b=c=' do
- From: Eric <einazaki668@xxxxxxxxx>
- Date: Thu, 22 Dec 2011 20:27:57 -0800 (PST)
On Dec 21, 5:44 pm, Steven D'Aprano <steve
Yes, you should create your lists before trying to append to them.
But you aren't forced to use a for-loop. You can use a list comprehension:
x = [some_function(a) for a in range(n)]
Notice that here you don't need x to pre-exist, because the list comp
creates a brand new list, which then gets assigned directly to x.
Now to my actual question. I need to do the above for multiple arrays
(all the same, arbitrary size). So I do this:
This creates one empty list object, and gives it three names, x, y and z.
Every time you append to the list, all three names see the same change,
because they refer to a single list.
Except it seems that I didn't create three different arrays, I created
one array that goes by three different names (i.e. x, y and z all
reference the same pile of numbers, no idea which pile).
This surprises me, can someone tell me why it shouldn't?
Because that's the way Python works. Python is an object-oriented, name
binding language. This is how OO name binding works: you have a single
object, with three names bound to it. The above line is short-cut for:
a = 
b = a
c = a
Python does not make a copy of the list unless you specifically instruct
I figure if I
want to create and initialize three scalars the just do "a=b=c=7",
That creates a single integer object with value 7, and binds three names
to it, *exactly* the same as the above.
If you could modify int objects in place, like you can modify lists in
place, you would see precisely the same effect. But ints are immutable:
all operations on ints create new ints. Lists are mutable, and can be
changed in place.
example, so why not extend it to arrays. Also, is there a more pythonic
way to do "x=, y=, z="?
Well that literally won't work, you can't separate them by commas.
Newlines or semicolons will work.
Or: x, y, z = , , 
Either is pretty Pythonic.
Thanks to you and Dennis for the quick lesson and tips. Very helpful
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