Re: file pointer array
- From: Ben Finney <ben+python@xxxxxxxxxxxxxxx>
- Date: Tue, 05 Jun 2012 11:38:18 +1000
FSH <lee.joosang@xxxxxxxxx> writes:
I have a simple question. I wish to generate an array of file
pointers.
Welcome to Python.
By your description, I think you want a different type: not an array,
but a list.
I recommend you become familiar with Python's data model
<URL:http://docs.python.org/reference/datamodel.html>.
I wish to generate fine pointer array so that I can read the files at
the same time.
I don't know about reading the files *at the same time*.
If you mean you want to have multiple files open simultaneously and read
from any of them arbitrarily, you don't need any particular container
type; you just need to have references to those open file objects.
Any references will do for that; you don't need pointers in Python.
for index in range(N):
fid[index] = open('data%d.txt' % index,'r')
Python has iterable types built in, so you rarely need to maintain an
index yourself.
Further, Python has “list comprehension”, allowing you to define a list
in a single statement by describing how each element is created::
fid = [open('data%d.txt' % count, 'r') for count in range(N)]
To learn about this and other useful topics, you should work through
Python's tutorial <URL:http://docs.python.org/tutorial/> from start to
finish, doing each exercise until you understand the concept being
explained.
--
\ “We have to go forth and crush every world view that doesn't |
`\ believe in tolerance and free speech.” —David Brin |
_o__) |
Ben Finney
.
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