Re: Matching of optional parts in regular expressions

From: Ulrich Schöbel (usus_at_aladyn.de)
Date: 07/08/04 

Date: Thu, 8 Jul 2004 18:03:47 +0200

In article <40ed1d8f.0407080602.bd6de25@posting.google.com>,
        Markus.Elfring@web.de (Markus Elfring) writes:
> Does this example show an error in the implementation?

No. All three examples work absolutely correct.

>
> % regexp {\s*(\d+)(?:%(\w+))?} { !123!} z a b
> 1
> % foreach X {a b} {puts "$X=|[set $X]|"}
> a=|123|
> b=||

Regex is not anchored. It matches no whitespace (\s*),
three digits (\d+) and no word introduced by a % sign.

> % regexp {\s*(\d+)(?:%(\w+))?$} { !123!} z a b
> 0

Same as before, but anchored at the end. The final ! is
not matched, so the entire regex doesn't match.

> % regexp {\s*(\d+)(?:%(\w+))?} { 456%} z a b
> 1
> % foreach X {a b} {puts "$X=|[set $X]|"}
> a=|456|
> b=||

Same as first example.

>
> I think that the specified strings must not match to the pattern.
> How do you think about it?

Everything is working ok.

Best regards

Ulrich 

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